How old is Veronica E Bitkower?
Veronica E Bitkower is possibly 79 years old and maybe was born in January 1947.
Next Steps: Find a result that matches whom you're looking for the most. Once you find a match, click "Search For Background Reports" to continue. Or use the form below to find the person you are searching for.
By clicking “SEARCH” I agree to the current USSearch TERMS OF USE and PRIVACY POLICY, and agree not use the products or services of USSearch to determine one's eligibility for credit, housing, insurance, employment or any other reason subject to the Fair Credit Reporting Act (“FCRA”). I further understand that USSearch is not a “consumer reporting agency” and does not provide “consumer reports” under the FCRA.
We have 2 records for Veronica Bitkower with an approximate age of 79 years old. Veronica has been found in 2 states including New Jersey and New York. On file we have 5 email addresses. And 9 phone numbers linked to Veronica, with area codes such as 201, 212, 646 and 718. The information below may also include images, social media accounts and more.
AKA (Aliases, nicknames, alternate spellings, married and/or maiden names):
voip
verizon new york inc
First Reported January 17, 2007
voip
verizon new jersey inc
First Reported October 15, 2005
555 North Ave Apt 22p
Fort Lee, New Jersey 07024
Bergen
Homes, rental properties, businesses, apartments, condos and/or other real estate associated with Veronica Bitkower.
5118 14th Ave Apt 5e
Brooklyn, New York 11219
Kings
Click here to search for background reports.
Veronica E Bitkower is possibly 79 years old and maybe was born in January 1947.
Veronica E Bitkower has been associated with 3 addresses, the last known one is 555 North Ave Apt 22p, Fort Lee, Nj 07024-2420.
Veronica E Bitkower has been known to have 9 phone numbers, including (212) 645-9551.
Veronica E Bitkower has been known to have 5 email addresses, including xxxxxx@aol.com.
Veronica E Bitkower's possible relatives include Caroline I Bitkower, Elsie Jane Bitkower, Lawren Bitkower and others.
Search by First Name
Search by Last Name